Governor Abubakar Atiku Bagudu has been declared winner of the governorship election in Kebbi State.
The presiding officer, professor Armu Yau Hamisu, said Bagudu of the All Progressives Congress (APC) emerged winner in the election, having scored the highest number of votes 673,717 with a difference of 567,084 against the 106,633 votes scored by the Peoples Democratic Party’s candidate, Senator Isa Galaudu, in the election.
The returning officer said the total registered voters is 1,789,075 while a total of 820078 were accredited for the election.
He said the total votes cast in the election was 814,084 while a total of 20,696 were rejected.
He said the “APC candidate, Abubakar Atiku Bagudu, having scored the highest number of votes in the election is hereby declared winner and returned”.
The APC candidate defeated his PDP opponent in all the 21 local government areas of the state.
Breakdown:
Yauri
APC-25,011
PDP-1,574
Arewa
APC-35,991
PDP-10,994
Gwandu
APC – 30,720
PDP -4,,526
Birnin Kebbi
APC-79,092
PDP-6010
Argungu
APC- 30101
PDP-23,397
Aliero
APC-21,923
PDP-3,479
Suru
APC -39,359
PDP-5,198
Shanga
APC-27,012
PDP-3,506
Kalgo
APC-21,899
PDP-805
Augie
APC-28,479
PDP-11,875
Bunza
APC- 23,980
PDP-2114
Dandi
APC-33,315
PDP-5,929
Sakaba
APC-19,182
PDP-1,746
Zuru
APC-25,507
PDP-4578
Jega
APC-53,807
PDP-1774
Maiyanma
APC-40,217
PDP-1,477
Bagudo
APC-41,556
PDP-2,581
Ngaski
APC-20,917
PDP-5,516
Fakai
APC-14,722
PDP-3,729
Danko-Wasagu
APC-29,625
PDP- 4,609
Koko/Besse
APC- 31,392
PDP-1,216
